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A Problem Course in Mathematical Logic by Stefan Bilaniuk

By Stefan Bilaniuk

An issue path in Mathematical common sense is meant to function the textual content for an advent to mathematical common sense for undergraduates with a few mathematical sophistication. It offers definitions, statements of effects, and difficulties, besides a few factors, examples, and tricks. the belief is for the scholars, separately or in teams, to benefit the fabric by means of fixing the issues and proving the implications for themselves. The booklet should still do because the textual content for a direction taught utilizing the converted Moore-method.

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2 As with LP , our formal language for propositional logic, first-order languages are defined by specifying their symbols and how these may be assembled into formulas. 1. The symbols of a first-order language L include: (1) (2) (3) (4) (5) (6) (7) Parentheses: ( and ). Connectives: ¬ and →. Quantifier: ∀. Variables: v0, v1, v2, . . , vn , . . Equality: =. A (possibly empty) set of constant symbols. For each k ≥ 1, a (possibly empty) set of k-place function symbols. (8) For each k ≥ 1, a (possibly empty) set of k-place relation (or predicate) symbols.

STRUCTURES AND MODELS given by s(x|m)(vk ) = s(vk ) if vk is different from x m if vk is x. If M |= ϕ[s], we shall say that M satisfies ϕ on assignment s or that ϕ is true in M on assignment s. We will often write M ϕ[s] if it is not the case that M |= ϕ[s]. Also, if Γ is a set of formulas of L, we shall take M |= Γ[s] to mean that M |= γ[s] for every formula γ in Γ and say that M satisfies Γ on assignment s. Similarly, we shall take M Γ[s] to mean that M γ[s] for some formula γ in Γ. 1. The key clause is 5, which says that ∀ should be interpreted as “for all elements of the universe”.

Note that deductions are finite sequences of formulas. 5. 4. 6. 4. 7. Assume, by way of contradiction, that ϕ ∈ / Σ. 2 and the Deduction Theorem to show that Σ must be inconsistent. 8. 9. 9. 8. 10. 7 and induction on a list of all the formulas of LP . 11. 2. 10, and define a truth assignment v by setting v(An) = T if and only if An ∈ Σ. Now use induction on the length of ϕ to show that ϕ ∈ Σ if and only if v satisfies ϕ. 12. 11. 13. 11. Part II First-Order Logic CHAPTER 5 Languages As noted in the Introduction, propositional logic has obvious deficiencies as a tool for mathematical reasoning.

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